Finding more minimum and maximum values in quadratic expressions part two



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Finding more minimum and maximum values in quadratic expressions part two



Complete the square in (15x² - 16x + 4) and find its minimum value and the x-value where the minimum value occurs.

15x² - 16x + 4 = {(15x - 8)² - 4} / 15

15x² - 16x + 4 >= -4 / 15

{(15x - 8)² - 4} / 15 >= -4 / 15

minimum value = -4 / 15

(15x - 8)² = 0

x = 8 / 15

 

Complete the square in (15x² - 19x + 6) and find its minimum value and the x-value where the minimum value occurs.

15x² - 19x + 6 = {(30x - 19)² - 1} / 60

15x² - 19x + 6 >= -1 / 60

{(30x - 19)² - 1} / 60 >= -1 / 60

minimum value = -1 / 60

(30x - 19)² = 0

x = 19 / 30

 

Complete the square in (25x² - 25x + 6) and find its minimum value and the x-value where the minimum value occurs.

25x² - 25x + 6 = {(10x - 5)² - 1} / 4

25x² - 25x + 6 >= -1 / 4

{(10x - 5)² - 1} / 4 >= -1 / 4

minimum value = -1 / 4

(10x - 5)² = 0

x = 1 / 2


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0 只獸收藏了此作品
  • 瀏覽量:276
  • 分級:普通級(General) - 全年齡皆可觀看
  • 發佈時間:2021-12-01 10:02